document.write( "Question 747825: 119/(2.718^(6x) - 14) = 7 \n" ); document.write( "
Algebra.Com's Answer #455175 by Edwin McCravy(20056)\"\" \"About 
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document.write( "\"119%2F%282.718%5E%286x%29+-+14%29%29\"\"%22%22=%22%22\"\"7\"\r\n" );
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document.write( "Multiply both sides by 2.7186x - 14\r\n" );
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document.write( "\"119%2F%282.718%5E%286x%29+-+14%29%29\"\"%22%22%2A%22%22\"\"%282.718%5E%286x%29+-+14%29\"\"%22%22=%22%22\"\"7%282.718%5E%286x%29+-+14%29%29\" \r\n" );
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document.write( "Cancel on the left, distribute on the right:\r\n" );
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document.write( "\"119%2F%28cross%282.718%5E%286x%29+-+14%29%29%29\"\"%22%22%2A%22%22\"\"%28cross%282.718%5E%286x%29+-+14%29%29\" = \"7%2A2.718%5E%286x%29+-+98%29\"\r\n" );
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document.write( "119 = 7·2.7186x - 98\r\n" );
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document.write( "Add 98 to both sides:\r\n" );
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document.write( "217 = 7·2.7186x\r\n" );
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document.write( "Divide both sides by 7\r\n" );
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document.write( "31 = 2.7186x\r\n" );
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document.write( "Take natural logarithms of both sides:\r\n" );
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document.write( "ln(31) = ln(2.7186x)\r\n" );
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document.write( "Use the rule of lags that allows you to write the\r\n" );
document.write( "log of an exponential as the exoponent multiplied\r\n" );
document.write( "by the log of the vase of the exponential.\r\n" );
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document.write( "ln(31) = 6x·ln(2.718)\r\n" );
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document.write( "divide both sides by 6·ln(2.718)\r\n" );
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document.write( "\"ln%2831%29%2F%286ln%282.718%29%29\" = x\r\n" );
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document.write( "0.5723905486 = x\r\n" );
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document.write( "[Note that 2.718 is a close approximation to e = 2.718281828459...]\r\n" );
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document.write( "Edwin

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