document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747078>Question 747078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the perimeter of a field is 266 ft and the length is 43 foot longer than the width what are the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455138 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2 x length + 2 x width<BR>\n" );
document.write( " length = (x + 43) width = x<BR>\n" );
document.write( "Perimeter => 2(x + 43) + 2x = 266<BR>\n" );
document.write( "          => 4x + 86 = 266<BR>\n" );
document.write( "                  4x = 266 - 86<BR>\n" );
document.write( "                  4x = 180<BR>\n" );
document.write( "                   x = 45<BR>\n" );
document.write( " Therefore length = 88 ft<BR>\n" );
document.write( "            width = 45 ft<BR>\n" );
document.write( "         </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );