document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747735>Question 747735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The longer leg of a right triangle is 2 cm more than twice the shorter leg. Find the measure of each leg of the triangle with the smallest possible area. \r<BR>\n" );
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document.write( "Please help me to answer. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455132 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given\r<BR>\n" );
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document.write( "The longer leg of a right triangle is 2 cm more than twice the shorter leg. Find the measure of each leg of the triangle with the smallest possible area.\r<BR>\n" );
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document.write( "Area = 1/2 * base * height\r<BR>\n" );
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document.write( "let x be the shorter leg and 2x+2 is the longer leg\r<BR>\n" );
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document.write( "then Area = 1/2*x*2(x+1) = x^2+x\r<BR>\n" );
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document.write( "Assuming values of x are whole numbers, then\r<BR>\n" );
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document.write( "if x = 1cm, then Area = 2cm^2 and the longer leg is 4cm\r<BR>\n" );
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