document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747762>Question 747762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The shadow of a building is 63,7m long when the angle of elevation of the sun is 61,5 degrees. Calculate the height of the building. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455110 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use Trigonometric ratios namely tan.<BR>\n" );
document.write( "The building represents the opposite <BR>\n" );
document.write( "while the length of the shadow is the <BR>\n" );
document.write( "adjacent.<BR>\n" );
document.write( "So tan 61.5 degs = opposite/63.7<BR>\n" );
document.write( "   tan 61.5 degs. x 63.7 = opposite<BR>\n" );
document.write( "    opposite = 117.32 metres. </SPAN>\n" );
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