document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747682>Question 747682</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (Hi... I'm Dannielle. 8th grade student taking Algebra1) I'm confused... on a preparation packet that's 10% of my grade... Lovely isn't it? Yet another thing my Algebra1 teacher never got the chance to teach. The question says: \"A function of g is described : g(x)=(x-3)2 +6... The domain of g is all real numbers greater than 0. The range of g is all real numbers greater than or equal to - A.) 9, B.) 6, C.) 3, D.) -3... \" Okay... correct me if I'm wrong, but does g(x) mean basically the same thing as the f(x) but the function is just labeled g instead of f? Yes? No? Sigh.. Okay. All I could think of doing was starting by factoring out the original equation but I just got x2-3x+15. I'm almost positive that I did that wrong and to be completely honest I'm not exactly sure that was what I was supposed to be doing to get the answer. Any suggestions or help would be greatly appreciated... (PS: I don't know if I'm asking this in the correct category so my apologies if this is the wrong one to be asking this is! ) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455077 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10553)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (Hi... I'm Dannielle. 8th grade student taking Algebra1) I'm confused... on a preparation packet that's 10% of my grade... Lovely isn't it? Yet another thing my Algebra1 teacher never got the chance to teach. The question says: \"A function of g is described : g(x)=(x-3)2 +6... The domain of g is all real numbers greater than 0. The range of g is all real numbers greater than or equal to - A.) 9, B.) 6, C.) 3, D.) -3... \" Okay... correct me if I'm wrong, but does g(x) mean basically the same thing as the f(x) but the function is just labeled g instead of f? Yes? No? Sigh.. Okay. All I could think of doing was starting by factoring out the original equation but I just got x2-3x+15. I'm almost positive that I did that wrong and to be completely honest I'm not exactly sure that was what I was supposed to be doing to get the answer. Any suggestions or help would be greatly appreciated... (PS: I don't know if I'm asking this in the correct category so my apologies if this is the wrong one to be asking this is! )\r<BR>\n" );
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document.write( "The smallest value of g(x) is when x = 3, as when 3 is substituted for x into the function, g(x) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x+-+3%29%5E2+%2B+6 ALIGN=MIDDLE  ALT=\"%28x+-+3%29%5E2+%2B+6\"   DISABLED_style= \"max-width:90%; height:auto;\" >, we get: g(3) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283+-+3%29%5E2+%2B+6 ALIGN=MIDDLE  ALT=\"%283+-+3%29%5E2+%2B+6\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which equals 6. Any other real number value, negative or positive, that's substituted will result in a larger value than 6. \r<BR>\n" );
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document.write( "Therefore, the range of g, or g(x) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28all_+reals_%3E=+6%29 ALIGN=MIDDLE  ALT=\"highlight_green%28all_+reals_%3E=+6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > )(CHOICE B). </SPAN>\n" );
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