document.write( "Question 747653: Starting from home,James traveled uphill to the office supply store for 75 minutes for 4 mph. He traveled back home along the same path downhill at a speed of 12 mph. What is the average speed for the entire trip from home to the office supply store and back? \n" ); document.write( "
Algebra.Com's Answer #455072 by MathTherapy(10555)\"\" \"About 
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Starting from home,James traveled uphill to the office supply store for 75 minutes for 4 mph. He traveled back home along the same path downhill at a speed of 12 mph. What is the average speed for the entire trip from home to the office supply store and back? \r
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\n" ); document.write( "\n" ); document.write( "Distance to supply store = \"%2875%2F60%29+%2A+4\", or \"%285%2F4%29+%2A+%284%2F1%29\", or 5 miles
\n" ); document.write( "Since distance to store is 5 miles, then distance back home = 5 miles also
\n" ); document.write( "Therefore, time taken to travel home = \"5%2F12\" hr\r
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\n" ); document.write( "\n" ); document.write( "Average speed = Total distance ÷ total time\r
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\n" ); document.write( "\n" ); document.write( "Average speed = \"%285+%2B+5%29%2F%285%2F4+%2B+5%2F12%29\" ------- \"10%2F%2815%2F12+%2B+5%2F12%29\" ------ \"10%2F%2820%2F12%29\"\r
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\n" ); document.write( "\n" ); document.write( "Average speed = \"10%2F1\" ÷ \"20%2F12\" ------ \"10%2F1\" * \"12%2F20\" ------ \"cross%2810%29%2F1\" * \"6cross%2812%29%2Fcross%282%29cross%2820%29\" ------ \"6%2F1\", or \"highlight_green%286%29\" mph
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