document.write( "Question 747655: Please help me solve this equation: \"+1%2F%28m%5E2-m%29+%2B+1%2F%28m%29+=+5%2F%28m%5E2-m%29+\"
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Algebra.Com's Answer #455046 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1/(m^2-m) + 1/(m) = 5/(m^2-m)
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\n" ); document.write( "Multiply thru by m(m^2-m) to get:
\n" ); document.write( "m + m^2-m = 5m
\n" ); document.write( "m^2 - 5m = 0
\n" ); document.write( "m(m-5) = 0
\n" ); document.write( "m = 0 or m = 5
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\n" ); document.write( "\"m\" cannot be zero because it is one of the denominators.
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\n" ); document.write( "Solutiion: m = 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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