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document.write( "The admission fee for a fair is $3 for children and $5 for adults. On a certain day, 2600 people enter the fair and $9600 is collected. How many children attended the fair? \n" );
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Algebra.Com's Answer #455029 by checkley79(3341) ![]() You can put this solution on YOUR website! C+A=2600 OR C=2600-A \n" ); document.write( "3C+5A=9600 \n" ); document.write( "3(2600-A)+5A=9600 \n" ); document.write( "7800-3A+5A=9600 \n" ); document.write( "2A=9600-7800 \n" ); document.write( "2A=1800 \n" ); document.write( "A=1800/2 \n" ); document.write( "A=900 ADULTS ANS. \n" ); document.write( "C=2600-900 \n" ); document.write( "C=1700 CHILDREN ANS. \n" ); document.write( "PROOF: \n" ); document.write( "3*1700+5*900=9600 \n" ); document.write( "5100+4500=9600 \n" ); document.write( "9600=9600 \n" ); document.write( " |