document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=628273>Question 628273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 5 machines complete a certain task in 12 days, how many machines are needed to finish the same task in 10 days? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454997 by </B><A HREF=/tutors/aboutme.mpl?userid=hibiskus><B>hibiskus(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hibiskus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 12 then 5. If 10 then how many?\r<BR>\n" );
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document.write( "12 -> 5\r<BR>\n" );
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document.write( "10 -> x\r<BR>\n" );
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document.write( "now by forming the rate we have this\r<BR>\n" );
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document.write( "12/10=5/x\r<BR>\n" );
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document.write( "and it's not direct proportion then we have\r<BR>\n" );
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document.write( "12/10=x/5 after multiplication side to side by 10 we have\r<BR>\n" );
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document.write( "12=2*x\r<BR>\n" );
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document.write( "x=6\r<BR>\n" );
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document.write( "there are 6 machines<BR>\n" );
document.write( "have a nice day </SPAN>\n" );
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