document.write( "Question 706108: Eight men can finish a painting job in 10 days. If the task needs to be completed 2 days ahead of schedule, how many men will be needed? \n" ); document.write( "
Algebra.Com's Answer #454993 by hibiskus(3)![]() ![]() ![]() You can put this solution on YOUR website! Inversely Proportional: when one value decreases at the same rate that the other increases. Than in our examples \r \n" ); document.write( "\n" ); document.write( "when days coming down number of men goes up and we have\r \n" ); document.write( "\n" ); document.write( "for directly propotional \n" ); document.write( "If x then y. If x is changed to a then what will be the value of y? \n" ); document.write( "formula\r \n" ); document.write( "\n" ); document.write( "x->y \n" ); document.write( "a-> \n" ); document.write( "\n" ); document.write( "for Inversely propotional \n" ); document.write( "If x then y. If x is changed to a then what will be the value of y? \n" ); document.write( "formula\r \n" ); document.write( "\n" ); document.write( "x->y \n" ); document.write( "a-> \n" ); document.write( "\n" ); document.write( "Eight men can finish a painting job in 10 days. If the task needs to be completed 2 days ahead of schedule, how many men will be needed?\r \n" ); document.write( "\n" ); document.write( "If 10 then 8. If 8 then how many?\r \n" ); document.write( "\n" ); document.write( "10->8 \n" ); document.write( "8-> \n" ); document.write( "\n" ); document.write( "the result is 10 men to finish a paininting job in 8 days. :) \n" ); document.write( " |