document.write( "Question 706108: Eight men can finish a painting job in 10 days. If the task needs to be completed 2 days ahead of schedule, how many men will be needed? \n" ); document.write( "
Algebra.Com's Answer #454993 by hibiskus(3)\"\" \"About 
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Inversely Proportional: when one value decreases at the same rate that the other increases. Than in our examples \r
\n" ); document.write( "\n" ); document.write( "when days coming down number of men goes up and we have\r
\n" ); document.write( "\n" ); document.write( "for directly propotional
\n" ); document.write( "If x then y. If x is changed to a then what will be the value of y?
\n" ); document.write( "formula\r
\n" ); document.write( "\n" ); document.write( "x->y
\n" ); document.write( "a->\"%28a%2Fx%29%2Ay\"\r
\n" ); document.write( "\n" ); document.write( "for Inversely propotional
\n" ); document.write( "If x then y. If x is changed to a then what will be the value of y?
\n" ); document.write( "formula\r
\n" ); document.write( "\n" ); document.write( "x->y
\n" ); document.write( "a->\"%28x%2Fa%29%2Ay\"\r
\n" ); document.write( "\n" ); document.write( "Eight men can finish a painting job in 10 days. If the task needs to be completed 2 days ahead of schedule, how many men will be needed?\r
\n" ); document.write( "\n" ); document.write( "If 10 then 8. If 8 then how many?\r
\n" ); document.write( "\n" ); document.write( "10->8
\n" ); document.write( "8->\"%2810%2F8%29%2A8=10\"\r
\n" ); document.write( "\n" ); document.write( "the result is 10 men to finish a paininting job in 8 days. :)
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