document.write( "Question 747502: Find the center and radius for the circle defined by the equation: x2 + y2 + 5x − y + 2 = 0 \n" ); document.write( "

Algebra.Com's Answer #454965 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
Put in \"standard form\" of a circle:
\n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2
\n" ); document.write( ".
\n" ); document.write( "x^2 + y^2 + 5x − y + 2 = 0
\n" ); document.write( "x^2 + y^2 + 5x − y = -2
\n" ); document.write( "x^2 + 5x + y^2 − y = -2
\n" ); document.write( "(x^2 + 5x) + (y^2 − y) = -2
\n" ); document.write( "(x^2 + 5x+ 25/4) + (y^2 − y + 1/4) = -2 +25/4+1/4
\n" ); document.write( "(x^2 + 5/2)^2 + (y^2 − 1/2)^2 = -8/4 +25/4+1/4
\n" ); document.write( "(x^2 + 5/2)^2 + (y^2 − 1/2)^2 = (-8+25+1)/4
\n" ); document.write( "(x^2 + 5/2)^2 + (y^2 − 1/2)^2 = 18/4
\n" ); document.write( "(x^2 + 5/2)^2 + (y^2 − 1/2)^2 = (3sqrt(2)/2)^2
\n" ); document.write( ".
\n" ); document.write( "center: (-5/2, 1/2)
\n" ); document.write( "radius: 3sqrt(2)/2
\n" ); document.write( " \n" ); document.write( "

\n" );