document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747461>Question 747461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a room is 1.5cm more than its breath.if the perimeter of the room is 63cm .find the lenth and breath of the room <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454941 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A perimeter = 2 lengths + 2 breadths<BR>\n" );
document.write( "If the length is 1.5 more than the<BR>\n" );
document.write( "breadth, then make length = (x + 1.5)<BR>\n" );
document.write( "This perimeter = 2 (x) + 2(x + 1.5)<BR>\n" );
document.write( "               = 2x + 2x + 3<BR>\n" );
document.write( "               = 4x + 3\r<BR>\n" );
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document.write( "       4x + 3 = 63<BR>\n" );
document.write( "       4x = 60<BR>\n" );
document.write( "        x = 15<BR>\n" );
document.write( "So breadth = 15 and length = 16.5<BR>\n" );
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