document.write( "Question 747422:
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document.write( "A rectangular flower garden
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document.write( "in a park is 30 feet wide and 40 feet long. A sidewalk
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document.write( "around the perimeter of the garden is being
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document.write( "planned, as shown in the figure. The gardener has
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document.write( "enough money to pour 624 square feet of cement
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document.write( "sidewalk. what is the width of the sidewalk. \r
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Algebra.Com's Answer #454912 by FrankM(1040)![]() ![]() You can put this solution on YOUR website! The new dimension is (2X+30)(2X+40) where x is the width of the walk. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we were simply solving for x, we'd have -39 as one answer, but since it's a problem with dimensions, we discard, and accept the 4 only. The walk is 4 feet wide.\r \n" ); document.write( "\n" ); document.write( "38 x 48 = 1824 or 624 more than the original 1200 \n" ); document.write( " |