document.write( "Question 747422:
\n" ); document.write( "A rectangular flower garden
\n" ); document.write( "in a park is 30 feet wide and 40 feet long. A sidewalk
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\n" ); document.write( "planned, as shown in the figure. The gardener has
\n" ); document.write( "enough money to pour 624 square feet of cement
\n" ); document.write( "sidewalk. what is the width of the sidewalk. \r
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Algebra.Com's Answer #454912 by FrankM(1040)\"\" \"About 
You can put this solution on YOUR website!
The new dimension is (2X+30)(2X+40) where x is the width of the walk. \r
\n" ); document.write( "\n" ); document.write( "\"%284x%5EX+%2B+140X+%2B+1200%29+-+624+=+1200\". New area less the walk equals original area\r
\n" ); document.write( "\n" ); document.write( "\"+%284X%5E2+%2B+140X+-+624%29+=+0+\". Subtract 1200 from both sides.\r
\n" ); document.write( "\n" ); document.write( "\"+X%5E2+%2B+35X+-+156+=+0+\". Divided both sides by 4\r
\n" ); document.write( "\n" ); document.write( "\"+%28X+%2B+39%29+%28X+-+4%29+\" \r
\n" ); document.write( "\n" ); document.write( "If we were simply solving for x, we'd have -39 as one answer, but since it's a problem with dimensions, we discard, and accept the 4 only. The walk is 4 feet wide.\r
\n" ); document.write( "\n" ); document.write( "38 x 48 = 1824 or 624 more than the original 1200
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