document.write( "Question 8276: Tony is 6 years older than his brother. 4 years ago, he was twice as old\r
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document.write( "How old is Tony
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document.write( "How old is his brother \n" );
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Algebra.Com's Answer #4549 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let T = Tony's age now and B = his brother's age now.\r \n" ); document.write( "\n" ); document.write( "T = B + 6 Tony is 6 years older than his brother. \n" ); document.write( "T - 4 = 2(B - 4) Tony's age 4 years ago (T-4) was twice his brother's age (2(B-4))\r \n" ); document.write( "\n" ); document.write( "Substitute T = B + 6 into the second equation, simplify and solve for B.\r \n" ); document.write( "\n" ); document.write( "(B + 6)-4 = 2(B - 4) \n" ); document.write( "B + 2 = 2B - 8 Subtract B from both sides. \n" ); document.write( "2 = B - 8 Add 8 to both sides. \n" ); document.write( "B = 10 His brother's age is 10 years. \n" ); document.write( "T = B + 6 = 10 + 6 = 16 Tony's age is 16 years. \n" ); document.write( " |