document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747270>Question 747270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation for voltage dividers in electronics stated in basic algebraic terms is:<BR>\n" );
document.write( "x=y(b/(a+b))<BR>\n" );
document.write( "As a and b represent resistor values I have the equations to solve for each of them. I have been able to figure out the steps to calculate for a, however, the steps to arrive at the formula for b has eluded me. The formula given is:<BR>\n" );
document.write( "b=(xa)/(y-x)<BR>\n" );
document.write( "I suppose I could just memorize the formula but I think I must be missing something very basic that I cannot work out the steps myself. Your help would be much appreciated. Glenn </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454884 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we need to solve\r<BR>\n" );
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document.write( "x=y(b/(a+b)) for b\r<BR>\n" );
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document.write( "divide both sides of = by y\r<BR>\n" );
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document.write( "x/y = b/(a+b)\r<BR>\n" );
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document.write( "cross multiply the two fractions and we get\r<BR>\n" );
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document.write( "x(a+b) = yb\r<BR>\n" );
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document.write( "xa+xb = yb\r<BR>\n" );
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document.write( "now group the terms with b on to same side of = sign\r<BR>\n" );
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document.write( "yb-xb = xa\r<BR>\n" );
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document.write( "factor out the b\r<BR>\n" );
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document.write( "b(y-x) = xa and\r<BR>\n" );
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document.write( "b = xa/(y-x)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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