document.write( "Question 747371: Knowing that x = 2 and log(base a)y = 3 calculate the numerical value of the following
\n" );
document.write( "a) log(base a)x^3y^2
\n" );
document.write( "b) log(base a) (a^3x^2/y^2)\r
\n" );
document.write( "\n" );
document.write( "Can you please help me out? Thanks so much in advance
\n" );
document.write( "Can you also show me the steps it would really help me understand:) \n" );
document.write( "
Algebra.Com's Answer #454865 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Knowing that x = 2 and log(base a)y = 3 calculate the numerical value of the following \n" ); document.write( "a) log(base a)x^3y^2 \n" ); document.write( "--- \n" ); document.write( "= loga(x^3)+loga(y^2) \n" ); document.write( "--- \n" ); document.write( "= 3loga(x) + 2loga(y) \n" ); document.write( "--- \n" ); document.write( "= 3loga(2) + 2loga(3) \n" ); document.write( "--- \n" ); document.write( "= loga(8) + loga(9) \n" ); document.write( "--- \n" ); document.write( "= loga(72) \n" ); document.write( "===================================== \n" ); document.write( "b) log(base a) (a^3x^2/y^2) \n" ); document.write( "---- \n" ); document.write( "= loga(a^3) + loga(x^2) - loga(y^2) \n" ); document.write( "---- \n" ); document.write( "= 3 + 2loga(2) -2loga(3) \n" ); document.write( "---- \n" ); document.write( "= 3 + loga(4) - loga(9) \n" ); document.write( "--- \n" ); document.write( "= 3 + loga[4/9] \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================== \n" ); document.write( " \n" ); document.write( " |