document.write( "Question 747325: Solve the equation for x and show all your work.
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\n" ); document.write( "6+ (x –5)/2=(x –7)/3\r
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\n" ); document.write( "\n" ); document.write( "Please help me solve this problems and each step in order to understand it.
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Algebra.Com's Answer #454821 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
First of all clear the brackets
\n" ); document.write( "6 + (x - 5)/2 => 6 + x -5/2 => x + 1/2
\n" ); document.write( "So the equation becomes:-
\n" ); document.write( "x + 1/2 = x - 7/3
\n" ); document.write( "To remove the lower numbers(2 and 3)
\n" ); document.write( "you find one number that both 2 and 3
\n" ); document.write( "will divide into. This is 6\r
\n" ); document.write( "\n" ); document.write( " 2 divides into 6 then 3 goes up to
\n" ); document.write( "multiply x + 1 = 3x + 3
\n" ); document.write( " 3 divides into 6 then 2 goes up to
\n" ); document.write( "multiply x - 7 = 2x - 14.\r
\n" ); document.write( "\n" ); document.write( "Now as both equations have the same denominator (6)
\n" ); document.write( "so we can equal one to the other.\r
\n" ); document.write( "\n" ); document.write( " 3x + 3 = 2x - 14
\n" ); document.write( " Sort out like terms
\n" ); document.write( " 3x - 2x = - 14 - 3
\n" ); document.write( " x = - 17\r
\n" ); document.write( "\n" ); document.write( "To check put x = -17 into:-\r
\n" ); document.write( "\n" ); document.write( " x + 1/2 => -17 + 1/2 = -8
\n" ); document.write( " x - 7/3 => -17 - 7/3 = -8 Both agree
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