document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=705438>Question 705438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the smallest number greater than 200 that is divisible by both 3 and 9\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454752 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is well known that if the digits of a number add to a multiple of 3 then so does the number (the same property holds for 9). We look for a number such that\r<BR>\n" );
document.write( "\n" );
document.write( "2_ _  is a minimum, and divides 9\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so we can see the least number possible must be 207\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );