document.write( "Question 151913: HOW MANY FOUR DIGIT NUMBERS CAN BE FORMED FROM 1,2,3,4,5,6,7 WHICH IS GREATER THAN 3400? \n" ); document.write( "
Algebra.Com's Answer #454722 by Levski123(6)![]() ![]() ![]() You can put this solution on YOUR website! Thing of it like this \n" ); document.write( "4 digit number X1 X2 X3 X4 > 3400 so 3401 the lowest possible number greater than 3401. We need to make sure that whatever combination of numbers we make we cannot have a number lower than this. To achieve this we do the following\r \n" ); document.write( "\n" ); document.write( "For X1 there are 5 possible numbers that we can use (3,4,5,6,7, 3 is counts because our lowest acceptable value is 3401 as we determined) for X2, we have 4 possible values (4,5,6,7, again the digit 4 is included, as it its withing our lowest limit. We can't have digit 1 because that means we will accept values like 31XX which is lower than the 3400). With that logic in mind X3 have 7 values, This is because it does not matter what value the X3 digit has as all values are greater than 0 (which is the lowest acceptable digit based on 3401). And finally for the last digit we can have 7 again also because because at this point our lowest possible number so far is 341X which is already bigger than the 3400... So X4 is 7.\r \n" ); document.write( "\n" ); document.write( "No using the fundamental counting principle to add up all the possible combinations we multiply each possible digit combination so X1 x X2 x X3 x X4 = 5x4x7x7 = 980 possible combinations higher than 3400 \n" ); document.write( " |