document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64980>Question 64980</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618250034/algebrahomeworkh>Pre-Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum or difference. - 11/12 - -7/15\r<BR>\n" );
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document.write( " Thanks sooooooo much! Happy Holidays! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45472 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the sum or difference. - 11/12 - -7/15  First off, lets rewrite it noting that (-)(-)=(+):\r<BR>\n" );
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document.write( "-11/12--7/15=\r<BR>\n" );
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document.write( "-11/12+7/15   Next we'll multiply both terms by 60/60.  (60 is the lowest common multiple (LCM) of 12 & 15).  We are doing this in order to get a common denominator for both terms.  When we get a common denomator, we can start simplifying the resulting fraction.\r<BR>\n" );
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document.write( "(-11/12)(60/60)+(7/15)(60/60)=\r<BR>\n" );
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document.write( "((-11)(5))/60+((7)(4))/60 simplifying we have:\r<BR>\n" );
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document.write( "(-55+28)/60=<BR>\n" );
document.write( "-27/60  reducing the fraction we get<BR>\n" );
document.write( "((-3)(9))/((3)(20))=\r<BR>\n" );
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document.write( "-9/20\r<BR>\n" );
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document.write( "Hope this helps.  Happy holidays----ptaylor </SPAN>\n" );
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