document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747116>Question 747116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2 fair dice are rolled what is the probability that the sum is at least 10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454710 by </B><A HREF=/tutors/aboutme.mpl?userid=mikeebsc><B>mikeebsc(26)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mikeebsc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, we need to see how many combinations of numbers => 10. \r<BR>\n" );
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document.write( "6+6 or<BR>\n" );
document.write( "6+5 or<BR>\n" );
document.write( "6+4 or<BR>\n" );
document.write( "5+6 or<BR>\n" );
document.write( "5+5 or<BR>\n" );
document.write( "4+6 or\r<BR>\n" );
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document.write( "Next we see the total number of possible outcomes from 2 dice:<BR>\n" );
document.write( "6*6=36\r<BR>\n" );
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document.write( "Now we calculate the probability using the formula:\r<BR>\n" );
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document.write( "number of possible outcomes in the event we are looking for/number of total possible outcomes. In this case it is 6/36 which can be reduced to 1/6. So:\r<BR>\n" );
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document.write( "P (sum >=10)= 1/6<BR>\n" );
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