document.write( "Question 747065: A father is 2 years younger than 3 times the age of his son. In 12 years, he will be 12 years younger than twice the age of his son will be. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #454679 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A father is 2 years younger than 3 times the age of his son. In 12 years, he will be 12 years younger than twice the age of his son will be. Find their present ages. \n" ); document.write( "---- \n" ); document.write( "Equations: \n" ); document.write( "f = 3s-2 \n" ); document.write( "f+12 = 2(s+12)-12 \n" ); document.write( "--------- \n" ); document.write( "Substitute for \"f\" and solve for \"s\": \n" ); document.write( "3s-2+12 = 2s+24-12 \n" ); document.write( "s+10 = 12 \n" ); document.write( "s = 2 yrs old (son's age now) \n" ); document.write( "--- \n" ); document.write( "f = 3s-2 = 3*2-2 = 4 yrs old (father's age now) \n" ); document.write( "---- \n" ); document.write( "Note: That doesn't make much sense. \n" ); document.write( "------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |