document.write( "Question 747065: A father is 2 years younger than 3 times the age of his son. In 12 years, he will be 12 years younger than twice the age of his son will be. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #454679 by stanbon(75887)\"\" \"About 
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A father is 2 years younger than 3 times the age of his son. In 12 years, he will be 12 years younger than twice the age of his son will be. Find their present ages.
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\n" ); document.write( "Equations:
\n" ); document.write( "f = 3s-2
\n" ); document.write( "f+12 = 2(s+12)-12
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\n" ); document.write( "Substitute for \"f\" and solve for \"s\":
\n" ); document.write( "3s-2+12 = 2s+24-12
\n" ); document.write( "s+10 = 12
\n" ); document.write( "s = 2 yrs old (son's age now)
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\n" ); document.write( "f = 3s-2 = 3*2-2 = 4 yrs old (father's age now)
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\n" ); document.write( "Note: That doesn't make much sense.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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