document.write( "Question 64976: GIVE THE CENTER OF THE CIRCLE WITH EQUATION x^2+2x+y^2-10y+22=0. \n" ); document.write( "

Algebra.Com's Answer #45466 by funmath(2933) $\"\"$ $\"About$

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GIVE THE CENTER OF THE CIRCLE WITH EQUATION x^2+2x+y^2-10y+22=0.
\n" ); document.write( "The standard form of the equation of a circle is $\"highlight%28%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2%29\"$ , (h,k)=center, r=radius
\n" ); document.write( "We complete the squares in order to put the equation in standard form.
\n" ); document.write( "x^2+2x+y^2-10y+22-22=0-22
\n" ); document.write( "x^2+2x+____+y^2-10y+_____=-22+_____+______
\n" ); document.write( "To complete the squares take (1/2) the coefficient of the middle term and add it to both sides of the equation.
\n" ); document.write( "x^2+2x+(2/2)^2+y^2-10y+(-10/2)^2=-22+(2/2)^2+(-10/2)^2
\n" ); document.write( "x^2+2x+(1)^2+y^2-10y+(-5)^2=-22+(1)^2+(-5)^2
\n" ); document.write( "x^2+2x+1+y^2-10y+25=-22+1+25
\n" ); document.write( "(x+1)^2+(y-5)^2=4
\n" ); document.write( "The center (h,k)=(-1,5)
\n" ); document.write( "If you were asked for the radius, it would be $\"sqrt%284%29=2\"$
\n" ); document.write( "Happy Calculating!!! \n" ); document.write( "

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