document.write( "Question 747012: how do you do log7(2-x)=log7(5x) \n" ); document.write( "
Algebra.Com's Answer #454650 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
we use the inverse property of logs/exponents:\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0A+log7%282-x%29=log7%285x%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0A7%5E+log7%282-x%29=7%5Elog7%285x%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "and the inputs are recovered:\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0A2-x=5x%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F3%0D%0A\"
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