document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64960>Question 64960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem: Solve A = 1/2 h(b1 + b2) for b2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45460 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve A = 1/2 h(b1 + b2) for b2\r<BR>\n" );
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document.write( "First lets divide both sides by 1/2h or h/2 (h cannot be zero) and we get:<BR>\n" );
document.write( "A/(h/2)=b1+b2 \r<BR>\n" );
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document.write( "We can show that A/(h/2)=2A/h so we have:\r<BR>\n" );
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document.write( "2A/h=b1+b2  subtract b1 from both sides and we get<BR>\n" );
document.write( "2A/h-b1=b2 or <BR>\n" );
document.write( " b2=(2A-b1h)/h\r<BR>\n" );
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document.write( "ck<BR>\n" );
document.write( "A=h/2(b1+(2A-b1h)/h)) simplifying we get:<BR>\n" );
document.write( "A=h/2(b1h+(2A-b1h))/h or<BR>\n" );
document.write( "A=(b1h+2A-b1h)/2<BR>\n" );
document.write( "A=2A/2=A\r<BR>\n" );
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document.write( "Hope this helps.  Happy holidays.---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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