document.write( "Question 744227: 7x + 5y =77\r
\n" ); document.write( "\n" ); document.write( "3x- 4y = -10
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Algebra.Com's Answer #454578 by Chipmonkcheeks(3)\"\" \"About 
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Call 7x + 5y = 77 equation I, and called 3x - 4y = -10 equation II.
\n" ); document.write( "Then from equation I, if you -5y from both sides of the equation:
\n" ); document.write( "\"7x+=+77+-+5y\" ,
\n" ); document.write( "Then dividing both sides by 7:
\n" ); document.write( "\"x+=+11+-+%285%2F7%29y\" .\r
\n" ); document.write( "\n" ); document.write( "We can then substitute this expression for x into equation II. This gives us:\r
\n" ); document.write( "\n" ); document.write( "\"3%2811+-+%285%2F7%29y%29+-+4y+=+-10\" .\r
\n" ); document.write( "\n" ); document.write( "Expanding the brackets:\r
\n" ); document.write( "\n" ); document.write( "\"33+-+%2815%2F7%29y+-+4y+=+-10\", which is equivalent to,\r
\n" ); document.write( "\n" ); document.write( "\"43+=+%2843%2F7%29y\", which gives us that\r
\n" ); document.write( "\n" ); document.write( "\"y+=+7\".\r
\n" ); document.write( "\n" ); document.write( "Then substituting this back into our expression for x gives us:
\n" ); document.write( "\"x+=+11+-+%285%2F7%29%2A7\",
\n" ); document.write( "which give us that
\n" ); document.write( "\"x+=+6\"\r
\n" ); document.write( "\n" ); document.write( "Best to check these answers by substituting them back into the original equations.
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