document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=746904>Question 746904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of the tangent line to the graph of<BR>\n" );
document.write( "a. f(x) = -2x^2+3x-2, at x=-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454551 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First obtain your y coordinate by<BR>\n" );
document.write( "substituting x = -2 into f(x)<BR>\n" );
document.write( "f(x) = -2(-2)^2 + 3(-2) - 2<BR>\n" );
document.write( "     =  -8 -6 -2<BR>\n" );
document.write( "     = -16      Coords are: {-2, -16}\r<BR>\n" );
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document.write( " Differentiate f(x)<BR>\n" );
document.write( "    f'(x) = - 4x + 3<BR>\n" );
document.write( "Substitute x = -2 into f'(x)<BR>\n" );
document.write( "     -4(-2) + 3  = 11  (gradient)\r<BR>\n" );
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document.write( "  Using y - b = m(x - a)<BR>\n" );
document.write( "        y + 16 = 11(x + 2)<BR>\n" );
document.write( "            y = 11x + 22 - 16<BR>\n" );
document.write( "            y = 11x + 6 </SPAN>\n" );
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