document.write( "Question 746886: Hello, I would really appreciate if someone could show me how to factor the following equation using the ac method. 8x^2-22x+5. I have been trying but can not figure out how to do it. Thank you so much for your help. \n" ); document.write( "

Algebra.Com's Answer #454539 by savvyhush23(50) $\"\"$ $\"About$

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Hello, I would really appreciate if someone could show me how to factor the following equation using the ac method. $\"8x%5E2-22x%2B5\"$ . I have been trying but can not figure out how to do it. Thank you so much for your help.
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\n" ); document.write( "Ok, a = 8 and c = 5, their product is 40, so the closest factors that gives the sum of -22 (the middle term) are -20 and -2.
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\n" ); document.write( "rewriting the -22x as -20x-2x: $\"8x%5E2-20x-2x%2B5\"$ , divide -20 by 8 and 5 by -2,
\n" ); document.write( "then factor by grouping: $\"8x%28x-5%2F2%29-2%28x-5%2F2%29\"$ , we have common factor $\"x-5%2F2%29\"$ ,
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\n" ); document.write( "then group again, $\"%288x-2%29%28x-5%2F2%29\"$ , and
\n" ); document.write( "simplying further divide -2 by 8, therefore, $\"8%28x-1%2F4%29%28x-5%2F2%29\"$ , answer!!! \n" ); document.write( "

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