document.write( "Question 746639: An outlet pipe can empty a cistern in 18 hours. With cistern full, this pipe and a second pipe are opened and together they empty 3/5 of the cistern in 6 hours. If the first pipe is then shut off, how long will it take the second pipe to finish emptying the cistern? \n" ); document.write( "
Algebra.Com's Answer #454504 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
An outlet pipe can empty a cistern in 18 hours.
\n" ); document.write( " With cistern full, this pipe and a second pipe are opened and together they empty 3/5 of the cistern in 6 hours.
\n" ); document.write( " If the first pipe is then shut off, how long will it take the second pipe to finish emptying the cistern?
\n" ); document.write( ":
\n" ); document.write( "Let t = time required by the 2nd pipe to empty the cistern
\n" ); document.write( "Let the completed job = 1 (An empty cistern)
\n" ); document.write( ":
\n" ); document.write( "\"this pipe and a second pipe are opened and together they empty 3/5 of the cistern in 6 hours.\"
\n" ); document.write( "\"6%2F18\" + \"6%2Ft\" = \"3%2F5\"
\n" ); document.write( "Multiply by 90t, resulting in:
\n" ); document.write( "5t(6) + 90(6) = 18t(3)
\n" ); document.write( "30t + 540 = 54t
\n" ); document.write( "540 = 54t - 30t
\n" ); document.write( "540 = 24t
\n" ); document.write( "t = 540/24
\n" ); document.write( "t = 22.5 hr for the 2nd pipe to empty the cistern alone
\n" ); document.write( ":
\n" ); document.write( "\"If the first pipe is then shut off, how long will it take the second pipe to finish emptying the cistern\"
\n" ); document.write( "Let f = time required for 2nd pipe to finish emptying the cistern
\n" ); document.write( "\"6%2F18\" + \"%28%28f%2B6%29%29%2F22.5\" = 1
\n" ); document.write( "multiply by the least common multiple of 18 and 22.5, 405, resulting in:
\n" ); document.write( "22.5(6) + 18(f+6) = 405
\n" ); document.write( "135 + 18f + 108 = 405
\n" ); document.write( "18f = 405 - 135 - 108
\n" ); document.write( "18f = 162
\n" ); document.write( "f = 162/18
\n" ); document.write( "f = 9 more hrs to finish
\n" ); document.write( "
\n" ); document.write( "
\n" );