document.write( "Question 746536: Solve the equation 4sin^2x-1=0 for x over the interval [0, 2π) \n" ); document.write( "
Algebra.Com's Answer #454492 by Cromlix(4381)\"\" \"About 
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4sin^2x - 1 + 0
\n" ); document.write( "4 sin^2x = 1
\n" ); document.write( " sin^x = 1/4
\n" ); document.write( "Take square root of both sides
\n" ); document.write( " sin x = + and - 1/2\r
\n" ); document.write( "\n" ); document.write( "Because the square root has been taken of the
\n" ); document.write( "angle both positive and negative values must
\n" ); document.write( "be included.\r
\n" ); document.write( "\n" ); document.write( " x = 30, 150, 210, 330, 390, 510,
\n" ); document.write( " 570, 690, 750, 870, 930.\r
\n" ); document.write( "\n" ); document.write( " [ interval 0, 960}
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