document.write( "Question 746756: In Triangle ABC, Angle B = 15 degrees less than twice angle A and Angle C is more than angle A. Find angle C. \n" ); document.write( "
Algebra.Com's Answer #454481 by tommyt3rd(5050)![]() ![]() You can put this solution on YOUR website! B=2A-15 \n" ); document.write( "C>A\r \n" ); document.write( "\n" ); document.write( "and A+B+C=180\r \n" ); document.write( "\n" ); document.write( "which becomes...\r \n" ); document.write( "\n" ); document.write( "A+(2A-15)+C=180\r \n" ); document.write( "\n" ); document.write( "C=180+15-3A\r \n" ); document.write( "\n" ); document.write( "C=165-3A\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which sets our boundary to test for valid triangles. After trial and error (there's probably a better way) we can deduce the following.\r \n" ); document.write( "\n" ); document.write( "The least value for C under these conditions is C=42 and the greatest is a little more than 142\r \n" ); document.write( "\n" ); document.write( "so...these are pretty good approximations \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |