document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=746610>Question 746610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the solution of the equation in the interval [0,2pi) algebraically. \r<BR>\n" );
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document.write( "sin^2x+cosx+1=0\r<BR>\n" );
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document.write( "Some quick help would be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454425 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the solution of the equation in the interval [0,2pi) algebraically. <BR>\n" );
document.write( "sin^2x+cosx+1=0<BR>\n" );
document.write( "1-cos^2x+cosx+1=0<BR>\n" );
document.write( "cos^2x-cosx-2=0<BR>\n" );
document.write( "(cosx-2)(cosx+1)=0<BR>\n" );
document.write( "cosx=2 (reject,(-1 &#8804; cosx &#8804; 1))<BR>\n" );
document.write( "or<BR>\n" );
document.write( "cosx=-1<BR>\n" );
document.write( "x=&#960; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );