document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=746666>Question 746666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object is propelled upward from the ground. The height of the object t seconds later is given by the equation h = -16tē + 32t , where h is measured in feet. After how many seconds does the object hit the ground? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454415 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454415\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h = -16t^2 +32t<BR>\n" );
document.write( "h= -16t (t-2)  (factored out -16t from both terms_\r<BR>\n" );
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document.write( "for-16t to equal 0, t = 0, i.e. object starts at ground<BR>\n" );
document.write( "t-2 = 0 at t = 2, so object isback down at 2 seconds. </SPAN>\n" );
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