document.write( "Question 26342: how many 6 number combinations will be made from 1 2 3 4 5 6 7 8 9, where 1 2 and 3 must appear on the 6-number combination? \n" ); document.write( "
Algebra.Com's Answer #454290 by Levski123(6)![]() ![]() ![]() You can put this solution on YOUR website! Because 1,2,3 must be in the 6 digits we only need to worry about 3 other digits, and how many possible combinations there for them. There are 9 possible digits and we are taking 3 at a time (remember we are working with combinations, order does not matter) So there are 9C3 combinations for the remaining three digits. When we combine all the possible combinations we get 1x1x1x9C3 to get the total 84 combinations \n" ); document.write( " |