document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=746423>Question 746423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 336 square inches. The length is 21 inches long. Find the width<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454273 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A perimeter would be measured in inches not <BR>\n" );
document.write( "square inches.<BR>\n" );
document.write( "I think you mean an area of 336 sq. inches.<BR>\n" );
document.write( "Area of a rectangle = l x b<BR>\n" );
document.write( " Therefore the width (breadth) = Area/length<BR>\n" );
document.write( " = 336/21 = 16 inches.<BR>\n" );
document.write( "If you mean that the perimeter = 336 inches<BR>\n" );
document.write( "and you have a length of 21 inches then you would double <BR>\n" );
document.write( "21 = 42 inches. Subtract 42 inches from 336 inches and divide <BR>\n" );
document.write( "by two = 147 inches for the width.<BR>\n" );
document.write( "A perimeter consists of two lengths and two widths<BR>\n" );
document.write( "in a rectangle. </SPAN>\n" );
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