document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4068>Question 4068</A>: <I><SPAN STYLE=\"word-break: break-all;\">   In how many ways can a committee of 3 be selected from a group of 5?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454241 by </B><A HREF=/tutors/aboutme.mpl?userid=Levski123><B>Levski123(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Levski123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the permutations formula<BR>\n" );
document.write( "nPr = n!/(n-r)!\r<BR>\n" );
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document.write( "5P3 = 5!/(5-3)!<BR>\n" );
document.write( "    = 5!/2!<BR>\n" );
document.write( "    = 5x4x3x2x1 / 2x1  <BR>\n" );
document.write( "    = 5x4x3<BR>\n" );
document.write( "    = 60<BR>\n" );
document.write( "The Number counting principle can also be applied, but its the same thing really.<BR>\n" );
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