document.write( "Question 746310: If 2x+3y=24 and 2x-3y=12 then value of xy is_____________ \n" ); document.write( "
Algebra.Com's Answer #454219 by mananth(16949)\"\" \"About 
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2.00 x + 3.00 y = 24.00 .............1
\n" ); document.write( "Total value
\n" ); document.write( "2.00 x -3.00 y = 12.00 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 1.00
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "2.00 x 3.00 y = 24.00
\n" ); document.write( "2.00 x -3.00 y = 12.00
\n" ); document.write( "Add the two equations
\n" ); document.write( "4.00 x = 36.00
\n" ); document.write( "/ 4.00
\n" ); document.write( "x = 9.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2.00 x + 3.00 y = 24.00
\n" ); document.write( "18.00 + 3.00 y = 24.00
\n" ); document.write( " 3.00 y = 24.00 -18.00
\n" ); document.write( " 3.00 y = 6.00
\n" ); document.write( " y = 2.00 \r
\n" ); document.write( "\n" ); document.write( "xy=9*2=18
\n" ); document.write( " \n" ); document.write( "
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