document.write( "Question 746292: a total of $7000 is invested: part at 9% and the remainder at 11%. How much is invested at each rate if the annual interest is $700 \n" ); document.write( "
Algebra.Com's Answer #454216 by mananth(16946)\"\" \"About 
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Part I 9.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 11.00% per annum ------------ Amount invested = y
\n" ); document.write( " 7000
\n" ); document.write( "Interest----- 700.00
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\n" ); document.write( "Part I 9.00% per annum ---x
\n" ); document.write( "Part II 11.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 7000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "9.00% x + 11.00% y= 700
\n" ); document.write( "Multiply by 100
\n" ); document.write( "9 x + 11 y= 70000.00 --------2
\n" ); document.write( "Multiply (1) by -9
\n" ); document.write( "we get
\n" ); document.write( "-9 x -9 y= -63000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 2 y= 7000
\n" ); document.write( "divide by 2
\n" ); document.write( " y = 3500
\n" ); document.write( "Part I 9.00% $ 3500
\n" ); document.write( "Part II 11.00% $ 3500
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\n" ); document.write( "CHECK
\n" ); document.write( "3500 --------- 9.00% ------- 315.00
\n" ); document.write( "3500 ------------- 11.00% ------- 385.00
\n" ); document.write( "Total -------------------- 700.00
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\n" ); document.write( "m.ananth@hotmail.ca
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