document.write( "Question 746292: a total of $7000 is invested: part at 9% and the remainder at 11%. How much is invested at each rate if the annual interest is $700 \n" ); document.write( "
Algebra.Com's Answer #454216 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 9.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 11.00% per annum ------------ Amount invested = y \n" ); document.write( " 7000 \n" ); document.write( "Interest----- 700.00 \n" ); document.write( " \n" ); document.write( "Part I 9.00% per annum ---x \n" ); document.write( "Part II 11.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 7000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "9.00% x + 11.00% y= 700 \n" ); document.write( "Multiply by 100 \n" ); document.write( "9 x + 11 y= 70000.00 --------2 \n" ); document.write( "Multiply (1) by -9 \n" ); document.write( "we get \n" ); document.write( "-9 x -9 y= -63000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 2 y= 7000 \n" ); document.write( "divide by 2 \n" ); document.write( " y = 3500 \n" ); document.write( "Part I 9.00% $ 3500 \n" ); document.write( "Part II 11.00% $ 3500 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "3500 --------- 9.00% ------- 315.00 \n" ); document.write( "3500 ------------- 11.00% ------- 385.00 \n" ); document.write( "Total -------------------- 700.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |