document.write( "Question 746278: If the perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions. \n" ); document.write( "

Algebra.Com's Answer #454215 by Cromlix(4381) $\"\"$ $\"About$

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Using x for length and y for breadth
\n" ); document.write( "Perimeter = 2x + 2y = 60
\n" ); document.write( "Area = xy = 200
\n" ); document.write( " x = 200/y\r
\n" ); document.write( "\n" ); document.write( "Substitute x = 200/y
\n" ); document.write( "in 2x + 2y = 60\r
\n" ); document.write( "\n" ); document.write( " 2(200/y)+ 2y = 60
\n" ); document.write( " 200/y + 2y - 60 = 0\r
\n" ); document.write( "\n" ); document.write( "Take to a common denominator
\n" ); document.write( "= y
\n" ); document.write( " 200 + 2y^2 - 60y = 0
\n" ); document.write( "rearrange
\n" ); document.write( " 2y^2 - 60y + 200
\n" ); document.write( " 2( y^2 - 30y + 100)
\n" ); document.write( " 2(y - 10)(y - 20)\r
\n" ); document.write( "\n" ); document.write( " Substitute y = 10 and y = 20
\n" ); document.write( " into 2x + 2y = 60\r
\n" ); document.write( "\n" ); document.write( " 2x + 2(10) = 60
\n" ); document.write( " 2x + 20 = 60
\n" ); document.write( " 2x = 40
\n" ); document.write( " x = 20\r
\n" ); document.write( "\n" ); document.write( " 2x + 2(20) = 60
\n" ); document.write( " 2x + 40 = 60
\n" ); document.write( " 2x = 20
\n" ); document.write( " x = 10\r
\n" ); document.write( "\n" ); document.write( "So either the length is 10 m and breadth is 20m
\n" ); document.write( "or
\n" ); document.write( "length is 20m and breadth is 10m \n" ); document.write( "

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