document.write( "Question 746193: Please help me solve this equation. I am having trouble finding all the steps.
\n" ); document.write( "log(16+2x)=log(x^2-4x)
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Algebra.Com's Answer #454187 by savvyhush23(50)\"\" \"About 
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Please help me solve this equation. I am having trouble finding all the steps.
\n" ); document.write( "log(16+2x)=log(x^2-4x)
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\n" ); document.write( "Is it finding x value in order for the function to be equal?
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\n" ); document.write( "If that so, since both side is in logarithm, you can eliminate log leaving:
\n" ); document.write( "\"16%2B2x=x%5E2-4x\" move 16 + 2x to the right,
\n" ); document.write( "\"x%5E2-4x-2x-16=0\"
\n" ); document.write( "\"x%5E2-6x-16=0\" the function is a quadratic equation, therefore to find x, use quadratic formula:\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a = 1, b = -6 and c = -16
\n" ); document.write( "\"x+=+%28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%2A1%2A%28-16%29+%29%29%2F%282%2A1%29+\"
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\n" ); document.write( "Therefore the answer are 8 and -2\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-5%2C+10%2C+-30%2C+10%2C+x%5E2-6x-16%29+\"
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