document.write( "Question 746164: Josee invests a total of $15 000.00 in two different investments. The first amount is put into a long-term account that pays interest at a rate of 6.5% per year. The second amount is put into a short-term account earning interest at a rate of 5% per year. Josee's investments earn a total of $885 in interest in one year. How much money did Josee put into each investment? \n" ); document.write( "

Algebra.Com's Answer #454172 by mananth(16946) $\"\"$ $\"About$

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Part I 6.50% per annum ---x
\n" ); document.write( "Part II 5.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 15000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "6.50% x + 5.00% y= 885
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6.5 x + 5 y= 88500.00 --------2
\n" ); document.write( "Multiply (1) by -6.5
\n" ); document.write( "we get
\n" ); document.write( "-6.5 x -6.5 y= -97500.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -1.5 y= -9000
\n" ); document.write( "divide by -1.5
\n" ); document.write( " y = 6000
\n" ); document.write( "Part I 6.50% $ 9000
\n" ); document.write( "Part II 5.00% $ 6000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "9000 --------- 6.50% ------- 585.00
\n" ); document.write( "6000 ------------- 5.00% ------- 300.00
\n" ); document.write( "Total -------------------- 885.00
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\n" ); document.write( "m.ananth@hotmail.ca
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