document.write( "Question 745948: how do you solve log x + log (3x + 5)= 1 \n" ); document.write( "
Algebra.Com's Answer #454080 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log x + log (3x + 5)= 1
\n" ); document.write( "log x(3x + 5)= 1
\n" ); document.write( "x(3x + 5)= 10^1
\n" ); document.write( "x(3x + 5)= 10
\n" ); document.write( "3x^2 + 5x= 10
\n" ); document.write( "3x^2 + 5x - 10 = 0
\n" ); document.write( "Applying the \"quadratic formula\" yields:
\n" ); document.write( "x = {1.17, -2.84}
\n" ); document.write( "throw out the negative solution (extraneous) leaving:
\n" ); document.write( "x = 1.17
\n" ); document.write( ".
\n" ); document.write( "Details of \"quadratic formula\" follows:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B5x%2B-10+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%285%29%5E2-4%2A3%2A-10=145\".
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\n" ); document.write( " Discriminant d=145 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-5%2B-sqrt%28+145+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%285%29%2Bsqrt%28+145+%29%29%2F2%5C3+=+1.17359909646538\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%285%29-sqrt%28+145+%29%29%2F2%5C3+=+-2.84026576313205\"
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\n" ); document.write( " Quadratic expression \"3x%5E2%2B5x%2B-10\" can be factored:
\n" ); document.write( " \"3x%5E2%2B5x%2B-10+=+3%28x-1.17359909646538%29%2A%28x--2.84026576313205%29\"
\n" ); document.write( " Again, the answer is: 1.17359909646538, -2.84026576313205.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B5%2Ax%2B-10+%29\"
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