Algebra.Com's Answer #454080 by nerdybill(7384)  You can put this solution on YOUR website! log x + log (3x + 5)= 1 \n" );
document.write( "log x(3x + 5)= 1 \n" );
document.write( "x(3x + 5)= 10^1 \n" );
document.write( "x(3x + 5)= 10 \n" );
document.write( "3x^2 + 5x= 10 \n" );
document.write( "3x^2 + 5x - 10 = 0 \n" );
document.write( "Applying the \"quadratic formula\" yields: \n" );
document.write( "x = {1.17, -2.84} \n" );
document.write( "throw out the negative solution (extraneous) leaving: \n" );
document.write( "x = 1.17 \n" );
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document.write( "Details of \"quadratic formula\" follows: \n" );
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document.write( " Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=145 is greater than zero. That means that there are two solutions: . \n" );
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document.write( " Quadratic expression can be factored: \n" );
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document.write( " Again, the answer is: 1.17359909646538, -2.84026576313205.\n" );
document.write( "Here's your graph: \n" );
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