document.write( "Question 745948: how do you solve log x + log (3x + 5)= 1 \n" ); document.write( "
Algebra.Com's Answer #454079 by savvyhush23(50)\"\" \"About 
You can put this solution on YOUR website!
how do you solve log x + log (3x + 5)= 1\r
\n" ); document.write( "\n" ); document.write( "Properties of Logarithm:
\n" ); document.write( "log M + log N = log MN
\n" ); document.write( "log (10) = 1\r
\n" ); document.write( "\n" ); document.write( "So, \"+log+%28%28x%29%29+%2B+log+%28%283x%2B5%29%29+=+1\"
\n" ); document.write( "\"log%28%28x%283x%2B5%29%29%29+=+log+%28%2810%29%29\"
\n" ); document.write( "\"log+%28%283x%5E2%2B5x%29%29+=+log+%28%2810%29%29\" eliminate log
\n" ); document.write( "\"3x%5E2%2B5x+=+10\"
\n" ); document.write( "\"3x%5E2%2B5x+-10=0\",it is a quadratic equation,\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B5x%2B-10+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%285%29%5E2-4%2A3%2A-10=145\".
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\n" ); document.write( " Discriminant d=145 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-5%2B-sqrt%28+145+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%285%29%2Bsqrt%28+145+%29%29%2F2%5C3+=+1.17359909646538\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%285%29-sqrt%28+145+%29%29%2F2%5C3+=+-2.84026576313205\"
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\n" ); document.write( " Quadratic expression \"3x%5E2%2B5x%2B-10\" can be factored:
\n" ); document.write( " \"3x%5E2%2B5x%2B-10+=+3%28x-1.17359909646538%29%2A%28x--2.84026576313205%29\"
\n" ); document.write( " Again, the answer is: 1.17359909646538, -2.84026576313205.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B5%2Ax%2B-10+%29\"

\n" ); document.write( "\n" ); document.write( " Therefore, x = {1.1736,-2.8403}
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