document.write( "Question 745952: find the value of x
\n" ); document.write( "log3 x = 4
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Algebra.Com's Answer #454076 by tommyt3rd(5050) $\"\"$ $\"About$

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$\"log3+x+=+4\"$ \r
\n" ); document.write( "\n" ); document.write( "the inverse to
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\n" ); document.write( " $\"log3%28x%29\"$ is $\"+3%5Ex\"$ \r
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\n" ); document.write( "\n" ); document.write( "so we raise both sides of the equation to 3\r
\n" ); document.write( "\n" ); document.write( " $\"3%5E%28log3+x%29+=+3%5E4\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x=81\"$ \r
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