document.write( "Question 745820: A farmer has 42 feet of fence with which to make a corral. If he arranges it into a rectangle that is twice as long as it is wide, what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #454036 by mykailao(6)\"\" \"About 
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The farmer has 42 ft. of fence. In the problem, he arranges it into a rectangle.
\n" ); document.write( "P (perimeter) = 42ft.
\n" ); document.write( "L (length) = 2x
\n" ); document.write( "W (width) = x
\n" ); document.write( "Recall that the perimeter of a rectangle is P = 2 (L+W)
\n" ); document.write( "Subsitute now the P, L and W.
\n" ); document.write( "The new equation is 42 = 2 (2x + x)
\n" ); document.write( "Use the distributive property. Therefore it will become 42 = 4x + 2x
\n" ); document.write( "Find now the x.
\n" ); document.write( "4x + 2x = 42
\n" ); document.write( "6x = 42
\n" ); document.write( "x = 7\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "L = 2(7) = 14ft.
\n" ); document.write( "W = x = 7ft. \r
\n" ); document.write( "\n" ); document.write( "Checking:
\n" ); document.write( "P = 2 (14 + 7)
\n" ); document.write( " = 2 (21)
\n" ); document.write( " = 42ft. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--There you go! :D
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