document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=745820>Question 745820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer has 42 feet of fence with which to make a corral. If he arranges it into a rectangle that is twice as long as it is wide, what are the dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #454033 by </B><A HREF=/tutors/aboutme.mpl?userid=savvyhush23><B>savvyhush23(50)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=savvyhush23><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=savvyhush23><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=454033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A farmer has 42 feet of fence with which to make a corral. If he arranges it into a rectangle that is twice as long as it is wide, what are the dimensions?\r<BR>\n" );
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document.write( "Perimeter = 42 ft.<BR>\n" );
document.write( "twice as long as it is wide: L=2W<BR>\n" );
document.write( "P = 2(L + W) = 2(2W + W) = 6W<BR>\n" );
document.write( "42 = 6W<BR>\n" );
document.write( "W = 7 ft. and L = 14 ft. </SPAN>\n" );
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