document.write( "Question 745825: If α and β are acute angles such that csc (α) = 17/15 and cot (β) = 3/4, find the following.\r
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document.write( "a. sin(α+β)\r
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document.write( "b.tan(α+β) \n" );
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Algebra.Com's Answer #454030 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! If α and β are acute angles such that csc (α) = 17/15 and cot (β) = 3/4, find the following. \n" ); document.write( "a. sin(α+β) \n" ); document.write( "b.tan(α+β) \n" ); document.write( "*** \n" ); document.write( "use a & b for (α & β \n" ); document.write( "csc(a)=17/15 \n" ); document.write( "sin(a)=15/17 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "cot(b)=3/4 \n" ); document.write( "tan(b)=4/3 \n" ); document.write( "opposite side=4 \n" ); document.write( "adjacent side=3 \n" ); document.write( "hypotenuse=5 \n" ); document.write( "sin(b)=4/5 \n" ); document.write( "cos(b)=3/5 \n" ); document.write( ".. \n" ); document.write( "sin(a+b)=sin(a)cos(b)+cos(a)sin(b)=(15/17)(3/5)+(8/17)(4/5)=(45/85)+(32/85)=77/85 \n" ); document.write( "tan(a+b)=(tan(a)+tan(b))/(1-tan(a)*tan(b)) \n" ); document.write( "=[(15/8)+(4/3)]/[1-(15/8)(4/3)] \n" ); document.write( "=[45/24+32/24]/[1-60/24]=77/24/-36/24=-77/36 \n" ); document.write( ".. \n" ); document.write( "Check with calculator: \n" ); document.write( "sin(a)=17/15 \n" ); document.write( "a≈61.9275º \n" ); document.write( "tan(b)=4/3 \n" ); document.write( "b≈53.1301 \n" ); document.write( "a+b=115.0526 \n" ); document.write( "sin(a+b)=sin(115.0526)≈0.9059 \n" ); document.write( "exact ans=77/85≈0.9059 \n" ); document.write( "tan(a+b)=tan(115.0526)=-2.139.. \n" ); document.write( "exact ans=-77/36≈-2.139.. \n" ); document.write( " |