document.write( "Question 745832: Find the product.\r
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document.write( "-2x(x2 - 3) \n" );
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Algebra.Com's Answer #454026 by lenny460(1073) You can put this solution on YOUR website! Find the product.\r \n" ); document.write( "\n" ); document.write( "-2x(x2 - 3) \r \n" ); document.write( "\n" ); document.write( "I will assume your expression is:\r \n" ); document.write( "\n" ); document.write( "-2x(x^2 - 3)\r \n" ); document.write( "\n" ); document.write( "We then expand:\r \n" ); document.write( "\n" ); document.write( "-2x * x^2 = -2x^3\r \n" ); document.write( "\n" ); document.write( "-2x * -3 = 6x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer:\r \n" ); document.write( "\n" ); document.write( "-2x^3 + 6x or\r \n" ); document.write( "\n" ); document.write( "6x - 2x^3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Lennox Obuong \n" ); document.write( "Algebra Tutor \n" ); document.write( "Nairobi, Kenya \n" ); document.write( "Email: obuong3@aol.com \n" ); document.write( " |