document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64936>Question 64936</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really need help with this one. I have factored both the numerator and denominator and came up with 2(4a-7)/(a-3)(a-5). The problem is:\r<BR>\n" );
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document.write( "5a-12/a^2-8a+15 minus 3a-2/a^2-8a+15\r<BR>\n" );
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document.write( "I am completely baffled by this problem. I need some serious help, please!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45399 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have done all the hard work but you have added rather than subtracted.<BR>\n" );
document.write( "The minus(3a-2) needs the -1( the 1 is implied) multiplied by the (3a-2) to give -3a+2.<BR>\n" );
document.write( "When you do the subtraction you end up with 2a-10 on the top which factorises to give 2(a-5) and the (a-5) will cancel with the one on the bottom.\r<BR>\n" );
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document.write( "I haven't given full instructions as you obviously know what you are doing and a small hint should be enough. </SPAN>\n" );
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