document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=745757>Question 745757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If theta is in quadrant III and tan (theta) = 2.4, then sec (theta) equals </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453989 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If theta is in quadrant III and tan (theta) = 2.4, then sec (theta) equals<BR>\n" );
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document.write( "sec^2 = tan^2 + 1 = 6.76<BR>\n" );
document.write( "|sec| = 2.6<BR>\n" );
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document.write( "In Q3 sec is negative<BR>\n" );
document.write( "sec = -2.6<BR>\n" );
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